# Find Three Largest Number

Learn to efficiently identify the three largest numbers in a sequence with this straightforward algorithm.

Published At

6/4/2021

Reading Time

~ 2 min read

Write a function that takes in an array of at least three integers and, without sorting the input array, returns a sorted array of the three largest integers in the input array.

The function should return duplicate integers if necessary; for example, it should return [10, 10, 12] for an input array of [10, 5, 9, 10, 12].

### Sample Input

`js``array = [141, 1, 17, -7, -17, -27, 18, 541, 8, 7, 7]`

`js``array = [141, 1, 17, -7, -17, -27, 18, 541, 8, 7, 7]`

### Sample Output

`js``[18, 141, 541]`

`js``[18, 141, 541]`

### Hints

**Hint 1**

Can you keep track of the three largest numbers in an array as you traverse the input array?

**Hint 2**

Following the suggestion in Hint #1, try traversing the input array and updating the three largest numbers if necessary by shifting them accordingly.

**Optimal Space & Time Complexity**

O(n) time | O(1) space - where n is the length of the input array

`js````
function findThreeLargestNumbers(array) {
if (array.length < 3) return;
let arr = []
for (let i = 0; i < 3; i++) {
let maximum = Math.max(...array)
let index = array.indexOf(maximum)
let temp = array.splice(index, 1)[0]
arr.push(temp)
}
return arr.sort((a, b) => a - b)
}
```

`js````
function findThreeLargestNumbers(array) {
if (array.length < 3) return;
let arr = []
for (let i = 0; i < 3; i++) {
let maximum = Math.max(...array)
let index = array.indexOf(maximum)
let temp = array.splice(index, 1)[0]
arr.push(temp)
}
return arr.sort((a, b) => a - b)
}
```

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Have a wonderful day.

Abhishek 🙏