Zero Sum Subarray

You're given a list of integers nums. Write a function that returns a boolean representing whether there exists a zero-sum subarray of nums.

A zero-sum subarray is any subarray where all the values add up to zero. A subarray is any contiguous section of the array. For the purposes of this problem, a subarray can be as small as one element and as long as the original array.

Sample Input

nums = [-5, -5, 2, 3, -2]

nums = [-5, -5, 2, 3, -2]

Sample Output

True // The subarray [-5, 2, 3] has a sum of 0

True // The subarray [-5, 2, 3] has a sum of 0

Hints

Hint 1

A good way to approach this problem is to first think of a simpler version. How would you check if the entire array sum is zero?

Hint 2

If the entire array does not sum to zero, then you need to check if there are any smaller sub-arrays that sum to zero. For this, it can be helpful to keep track of all the sums from [0, i], where i is every index in the array.

Hint 3

After recording all sums from [0, i], what would it mean if a sum is repeated?

Optimal Space & Time Complexity

O(n) time | O(n) space - where n is the length of nums

function zeroSumSubarray(nums) {
 
    for (let i = 0; i < nums.length; i++) {
      let sum = nums[i]
      if (sum === 0) {
        return true
      }
      
      for (let j = i + 1; j < nums.length; j++) {
        sum = sum + nums[j]
        if (sum === 0) {
          console.log(nums[i], nums[j])
          return true
        }
      }
    }
  
  return false;
}

function zeroSumSubarray(nums) {
 
    for (let i = 0; i < nums.length; i++) {
      let sum = nums[i]
      if (sum === 0) {
        return true
      }
      
      for (let j = i + 1; j < nums.length; j++) {
        sum = sum + nums[j]
        if (sum === 0) {
          console.log(nums[i], nums[j])
          return true
        }
      }
    }
  
  return false;
}

function zeroSumSubarray(nums) {
  // Write your code here.
  const sums = new Set([0])
  let currentSum = 0
  for (const num of nums) {
    currentSum += num
    if(sums.has(currentSum)) return true
    sums.add(currentSum)
  }
  return false
}

function zeroSumSubarray(nums) {
  // Write your code here.
  const sums = new Set([0])
  let currentSum = 0
  for (const num of nums) {
    currentSum += num
    if(sums.has(currentSum)) return true
    sums.add(currentSum)
  }
  return false
}

🧝‍♂️